Tuesday, 25 March 2014

TNPSC Assistant Engineer Jobs 2014

Apply Online for 98 TNPSC Assistant Engineer & Asst Director Jobs 2014:


Tamil Nadu Public Service Commission (TNPSC) invites applications for the recruitment of 98 Asst Engineer & Asst Director Posts through Combined Engineering Services Examination. Eligible candidates can apply online on or before 23-04-2014. Other details like age limit, qualification, selection, application fee, how to apply are given below


TNPSC Assistant Engineer Jobs 2014
TNPSC Assistant Engineer Jobs 2014

TNPSC Assistant Engineer Jobs Vacancy Details:

Total No of Posts: 98
Name of the Post:
1. Assistant Engineer (Civil), Water Resources Dept: 50 Posts
2. Assistant Engineer (Civil): 21 Posts
3. Assistant Engineer (Electrical): 09 Posts
4. Assistant Director of Industrial Safety and Health: 18 Posts

Age Limit for TNPSC Assistant Engineer Jobs:

Candidate’s age should be minimum 18 years for SC/ ST/ MBC/ DC/ BC/ BCM/ Widows and between 18 years to 30 years for others as on 01-07-2014.

TNPSC Assistant Engineer Jobs Educational Qualification:

Candidates should have BE degree in Civil Engineering or Civil and Structural Engineering or pass in Sections A & B of institution Exam for Sl No 1 & 2 and Degree in Electrical Engineering or ECE for Sl No 3 and Degree in Mechanical or Production/ Industrial/ Electrical/ Chemical Engineering or Textile Technology for Sl No 4.

TNPSC Assistant Engineer Jobs Selection Procedure:

Candidates are selected based on written test, Oral test and interview.

Application Fee for TNPSC Assistant Engineer Jobs 2014:

Candidates have to pay Rs.175/- through Online/ Offline and candidates claiming exception of fee have to pay Rs.50/- on or before 25-04-2014.
Online Mode: Candidates can pay the fee through Net Banking, Credit card, Debit Card.
Offline Mode: Candidates have to take System generated Challan and make payment at the nearest branch of Indian bank or Designated Post Offices. Make sure that the chalan is properly signed and the details of transaction number, branch name and DP code number, deposit date have been noted in the chalan by the branch authorities. Candidates can avail of the facility of one time Registration on payment of Rs.50/- towards Registration fee. The registration shall be valid for a period of Five years from the date of one time registration.

How to Apply for TNPSC Assistant Engineer Jobs 2014:

Eligible candidates can apply online from the website www.tnpsc.gov.in or www.tnpscexams.net on or before 23-04-2014.

Online Instructions for TNPSC Assistant Engineer Jobs 2014:

1. Before applying candidates have to scan photo and signature and have valid email id, mobile number.
2. Log on to the website www.tnpsc.gov.in or www.tnpscexams.net.
3. Click on Apply Online.
4. Select name of the post you are applying for .
5. If you already have Unique ID, enter the ID and password and view alreeady available information and update them if necessary.
6. If you do not have Valid ID enter all required fields.
7. Upload your photo and signature.
8. Click on Submit button.
9. You will get registration number and password and take print out of application, retain it for future reference.
10. Make Payment through online/ offline mode as mentioned above.

TNPSC Assistant Engineer Jobs 2014 - Important Dates:

Date of Notification: 24-03-2014.
Last Date for Submission of Application: 23-04-2014.
Last Date for Payment of Fee: 25-04-2014.
Date and Time of Written Examination Part- I: 27-07-2014 FN from 10:00 AM to 1:00 PM.
Date and Time of Written Examination Part- II: 27-07-2014 AN from 2:30 PM to 4:30 PM.

Physical Fitness for TNPSC Assistant Engineer Jobs 2014


Candidates selected for appointment to the post will be required to produce a certificate of
Physical fitness in the form prescribed below:

Name of the Post
Standard of Vision
Form of Certificate of Physical Fitness
Assistant Engineer (Civil & Electrical) PWD
Standard-III or better
Form prescribed for Executive post.
Assistant Director of Industrial Safety and Health
Standard-II or better

TNPSC Assistant Engineer Jobs 2014 Centres for Examination


TNPSC Assistant Engineer Jobs 2014 Centres

For more details regarding age limit, qualification, selection, application fee, how to apply, pay scale & other information click on the following link

Monday, 24 March 2014

Simple Interest Formula / Problems for Competitive Exams

Simple Interest Formula

S.I=[( P X N X R )/ 100 )].
Here,
P = Principle.
R = Rate per annum.
N= Number of years.

simple interest formula and problems
simple interest formula and problems

How to Calculate Simple Interest


What is Interest?
When borrowed a quantity of money from other for the personal or commercial purpose we pay some additional money to him after a certain period of time is called Interest. So we can also call this Interest as<b> Simple Interest. This type of problem is given in Quantitative Aptitude which is a very essential paper in banking exam.
What is Principle?
The money borrowed for a certain time period called<b> Principle or Sum.
What is Amount?
Addition of Simple Interest and Principle is called the amount.
Amount = Principle + Interest.

Simple Interest Formula & Problems 1

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
           

Simple Interest Formula & Problems 2


Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
(Xx14x2/100)+[(13900-x)x11x2/100]=3508
=>28x - 22x = 350800 - (13900 x 22)
=>6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

Simple Interest Formula & Problems 3


A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
Principal              
= Rs. [(100 x 4016.25)/(9x5)]                       
= Rs. (401625/45)            
= Rs. 8925.

Simple Interest Formula & Problems 4


How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?

Time = [(100 x 81)/(450x4.5)]      = 4 years.

Simple Interest Formula & Problems 5


 A sum of money gets doubled at 12% per annum. Then find the time?
solution:
 time= 100(n-1)/R
      =100(2-1)/12
      =100/12
      = 25/3 years

Simple Interest Formula & Problems 6


 A person borrows  x $ say $ 5000 for t years say 2 years at r1% say 4% per annum on simple interest. He uses his smartness and lends it to another person at bigger rate r2 % say 6.25% per annum for the same time. then his total gain in this transaction will be

={PT(r2-r1)}/100
= {5000*2(6.25-4)}/100
= 100*2.25
=  $ 225

Simple Interest Formula & Problems 7


The rate of interest on a sum of money is 4% per annum for the first 2 years, 6% per annum for the next 4 years and 8% per annum for the period beyond 6 years. If the simple interest accrued by the sum for the total period of 9 years is Rs 1120. What is the sum?

Ans= 2000

We suggest you to read Aptitude questions about Pipes and Cisterns

Simple Interest Formula & Problems 8


Two equal amount of money was deposited in two banks, each at 15% per annum, 3.5 years and 5 years respectively. If the difference between the interests is Rs 144, each sum is:

Ans= 640

Simple Interest Formula & Problems 9


If Rs. 64 Amount to Rs. 83.20 in 2 years, what will Rs. 86 amount to in 4 years at the same rate percent per annum?

Ans = 51.60

Simple Interest Formula & Problems 10


If Rs. 750 amounts to Rs. 1000 in 5 years, What will it become in 10 years at S.I?

Ans = 1250

Simple Interest Formula & Problems 11


How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% pa simple interest?

Ans = 56

Saturday, 22 March 2014

Pipes and cisterns Shortcut Methods, Formulas, Problems

Pipes and Cisterns Shortcut Methods


Pipe and Cistern problems are similar to time and work problems. A pipe is used to fill or empty the tank or cistern.
What is Inlet Pipe: A pipe used to fill the tank or cistern is known as Inlet Pipe.
What is Outlet Pipe: A pipe used to empty the tank or cistern is known as Outlet Pipe.

Pipes and Cisterns Shortcut Methods

Pipes and Cisterns Shortcut Methods


Pipes and Cisterns Shortcut Formulas

Pipes and Cisterns Formula 1:

Two pipes can fill (or empty) a cistern in x and y hours while working alone. If both pipes are opened together, then the time taken to fill (or empty) the cistern is given by (xy/(x+y)) hours

Pipes and Cisterns Formula 2:

Three pipes can fill (or empty) a cistern in x, y and z hours while working alone. If all the three pipes are opened together, the time taken to fill (or empty) the cistern is given by (xyz/(xy+yz+zx))hours

Pipes and Cisterns Formula 3:

If a pipe can fill a cistern in x hours and another can fill the same cistern in y hours, but a third one can empty the full tank in z hours, and all of them are opened together, then
Net Part filled in 1 hour = 1/x + 1/y - 1/z
Time taken to fill the full cistern = xyz/(yz+xz-xy)

Pipes and Cisterns Formula 4:


A pipe can fill a cistern in x hours. Because of a leak in the bottom, it is filled in y hours. If it is full, the time taken by the leak to empty the cistern is
xy/(y-x) hours 

Pipes and Cisterns basic formulas:


If an inlet pipe can fill the tank in x hours, then the part filled in 1 hour = 1/x
If an outlet pipe can empty the tank in y hours, then the part of the tank emptied in 1 hour = 1/y
If both inlet and outlet valves are kept open, then the net part of the tank filled in 1 hour is  1/x-1/y

Pipes and Cisterns Question 1


Two pipes A and B can fill a tank in 20 and 30 minutes respectively. If both the pipes are used together, then how long will it take to fill the tank?
Step1: Take L.C.M for 20 and 30
Step2: Tank capacity (L.C.M) is 60
Every min pipe A fill 3 part of the tank (60/20=3)
Every min pipe B fill 2 part of the tank (60/30=2)
Together filling so (3+2=5) 5 part of the tank is filling at Every min 12*5=60
Totally 60(L.C.M) parts will be fill in 12 minutes

Pipes and Cisterns Question 2

Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes, and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P,Q and R respectively. What is the proportion of the solution R in the liquid in the tank after 3 minutes?
Ans : 6/11

Pipes and Cisterns Question 3




Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:
Ans : 60/17 Hours

Pipes and Cisterns Question 4 

A pipe can fill a tank in 3 hours. Because of leak in the bottom, it is filled in 4 hours. If the tank is full, how much time will the leak take to empty it?
Pipes and Cisterns 1/3-1/4 =1/12
So leak will empty the tank in 12 hours.
(Apply this formula xy/(y-x) ans 12 hours)



Pipes and Cisterns Problem 5


Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, Pipe A is turned off. What is the total time required to fill the tank ?

Solution :Part of tank filled by A + B in 1 minute = ( 1 / 15 + 1 / 20 )
So tank filled by A + B in 4 minute = 4 ( 1 / 15 + 1 / 20 ) = 7 / 15
Part remaning = 1 - ( 7 / 15 ) = 8 / 15

1 / 20 part is filled by B in 1 minute

So, 8 / 15 part will be filled in = ( 20 / 1 )* ( 8 / 15 ) = 32 / 3 = 10 minutes 40 sec.

Pipes and Cisterns Problem 6


A cistern is normally filled in 8 hrs, but it takes four hrs longer to fill beacuse of a leak in the bottom. If the cistern is full , how much time the leak will empty it ?

Solution : Let the leak will empty the tank in x hrs.
Then part of cistern filled in 1 hr = ( 1 / 8 ) - ( 1 / x ) = x - 8 / 8x
So cistern will completly filled in 8x / x – 8
Ans : 24 hours

Pipes and Cisterns Problem 7


A tank is normally filled in 8 hrs. but takes 2 hrs.longer to fill because of leak in its bottom. If the cistern is full, in how many hours will the leak empty it?
Solution: When leak doesn’t work the tank is filled in 8 hrs.
When both filler pipe and leak work together, the tank is filled in 8+2 = 10 hrs.
Therefore, the time taken by leak to empty the tank = 8*10/ (10-8) = 40 Hours

Pipes and Cisterns Problem 8


A tank has a leak which would empty it in 8 hrs. A tap is turned on which admits 6 liters a minute in to the tank, and it is now emptied in 12 hrs. How many liters does the tank hold?
Solution: The time taken to fill the tank  12*8/(12-8) = 24 hours

Pipes and Cisterns Problem 9



An electric pump can fill a tank in 3 hours. Because of a leak in the tank, it took 3 (1/2)hours to fill the tank. If the tank is full, how much time will the leak take to empty it ?


Work done by the leak in 1 hour =[(1/3)-(1/(7/2))=1/3-7/2=1/21
The leak will empty the tank in 21 hours.
 

UPSC Geologist / Geo-Scientist Exam Eligibility 2014

UPSC Geologist & Geo-Scientist Exam Eligibility Details


UPSC Geologist & Geo-Scientist Exam Eligibility Details:
Union Public Service Commission (UPSC) Combined Geologist & Geo-Scientist Examination eligibility details are given below…

Before that read this
UPSC Geologist & Geo-Scientist Recruitment 2014

UPSC Geologist & Geo-Scientist Exam – Nationality Details

A candidate must be either:
  • a Citizen of India, or
  • a subject of Nepal, or
  • a subject of Bhutan, or
  • a Tibetan refugee who came over to India before the 1st January, 1962 with the intention of permanently settling in India. or
  • a person of Indian origin who has migrated from Pakistan, Burma, Sri Lanka or East African Countries of Kenya, Uganda, the United Republic of Tanzania, Zambia, Malawi, Zaire and Ethiopia or from Vietnam with the intention of permanently settling in India.
UPSC Geologist / Geo-Scientist Exam Eligibility 2014


Provided that a candidate belonging to categories (b), (c), (d) and (e) above shall be a person in whose favor a certificate of eligibility has been issued by the Government of India.

A candidate in whose case a certificate of eligibility is necessary, may be admitted to the examination but the offer of appointment may be given only after the necessary eligibility certificate has been issued to him/her by the Government of India.

UPSC Geologist & Geo-Scientist Exam Age Details

 Candidate age must be between 21 years and 32 years for Geologist, Geophysicist & Chemist posts, between 21 years and 35 years for Jr Hydrogeologist  posts.

UPSC Geologist & Geo-Scientist Exam Age Relaxation:


  • 5 years in case of SC/ST candidates
  • 3 years for OBC candidates.
  • Age is additionally relaxable by 5 years for those applicants who had ordinarily been domiciled in the Kashmir Division in the State of Jammu & Kashmir during the period 01-01-1980 to 31-12-1989.
  • 3 years for Defence Services personnel (disabled in operations during hostilities with any foreign country or in a disturbed area and released as a consequence thereof).
  • 5 years in case of ex-servicemen including Commissioned Officers and ECOs/SSCOs.
  • 10 years in the case of blind, deaf-mute and Orthopaedically handicapped persons.

Educational Qualification for UPSC Geologist & Geo-Scientist Exam


  1. For Geologists Gr ‘A’ in Geological Survey of India: Masters Degree in Geological Science or Geology or Geo-Exploration or Mineral Exploration or Engineering Geology or Marine Geology or Earth Science and Resource management or Oceanography and  Coastal Areas Studies or Petroleum Geosciences or Petroleum Exploration or Geochemistry or Geological Technology from a university incorporated by an Act of the central or State Legislature in India or an Educational Institution established by an Act of Parliament  or declared to be deemed university under section 3 of the University Grants Commission Act, 1956.
  2. For Geophysicists Gr ‘A’ in Geological Survey of India: M.Sc. in Physics or Applied Physics or M.Sc. (Geophysics) or Integrated M.Sc. (Exploration Geophysics) or M.Sc (Applied Geophysics) or M.Sc. (Marine Geophysics) or M.Sc. (Tech.) (Applied Geophysics) from a University incorporated by an Act of Parliament or State Legislature in India or other educational institutes established by an Act of the Parliament or declared to be deemed universities under the University Grants Commission Act, 1956.
  3. For Chemists Gr ‘A’ in Geological Survey of India: M. Sc. in Chemistry or Applied Chemistryor Analytical Chemistry from a University incorporated by an Act of Parliament or State Legislature or other educational Institutes established by an Act of the Parliament or declared to be deemed Universities under section 3 of the University Grants Commission Act, 1956 (3 of 1956) i.e. recognized University.
  4. For Junior Hydrogeologists (Scientist-B) Group ‘A’ in Central Ground Water Board: Masters Degree in Geology or Applied Geology or marine Geology from a from a university incorporated by an Act of the central or State Legislature in India or an Educational Institution established by an Act of Parliament or declared to be deemed university under section 3 of the University Grants Commission Act, 1956 or Masters Degree in Hydrogeology from a recognised university.


UPSC Geologist & Geo-Scientist Exam Physical standards

Candidates must be physically fit according to physical standards for admission to Combined Geo-Scientist & Geologist Examination as per the regulations specified in the examination notification.

UPSC Geologist & Geo-Scientist Recruitment 2014

UPSC Geologist Recruitment 2014

Union Public Service Commission (UPSC) conducts Combined Geologist & Geo-Scientist Examination 2014 for the recruitment of 265
  1. Geologist,
  2. Geophysicist,
  3. Chemist and
  4. Junior Hydrogeologist Posts.
Qualified candidates may apply online from 01-03-2014 to  31-03-2014 by 11:59 PM.
 For more details like UPSC Geologist Recruitment age limit, UPSC Geologist qualification, Geologist & Geo-Scientist selection process, UPSC Geologist & Geo-Scientist application fee, how to apply are given below

UPSC Geologist Recruitment 2014

UPSC Geologist Recruitment 2014

UPSC Geologist & Geo Scientist Vacancy Details 2014

Total No.of Posts: 265
Name of the Posts:
Category I: Posts in the Geological Survey of India, Ministry of Mines
1. Geologist: 260 Posts
  • Geologist Group A: 100 Posts
  • Geophysicist Group A: 80 Posts
  • Chemist Group A: 80 Posts
Category II: Posts in the Central Ground Water Board, Ministry of Water Resources
2. Geo-Scientist: 05 Posts
  • Junior Hydrogeologist (Scientist B) Group A: 05 Posts

UPSC Geologist Recruitment Age Limit:

Candidates age limit should be 21-32 years as on 01-08-2014 & should be born between 02-08-1982 to 01-08-1993 for (Sr.No:1) Posts, 21-35 years as on 01-08-2014 & should be born between 02-08-1979 to 01-08-1993 for (Sr.No:2) Posts. Age relaxation will be applicable as per rules.

UPSC Geologist Recruitment Educational Qualification:

Candidates should possess Masters Degree in Geological Science or Geology or Applied Geology etc in relevant discipline from a recognized university for Geologist Posts, M.Sc in Physics or Applied Physics or M.Sc (Geophysics) etc in relevant discipline form a University for Geophysicist Posts, M.Sc in Chemistry or Applied Chemistry or Analytical Chemistry from an University for Chemist Posts, Masters Degree in Geology or Applied Geology or Marine Geology from university for Junior Hydro-geologist Posts.

UPSC Geologist & Geo-Scientist Selection Process:

Candidates will be selected based on their performance in written test, interview/ personality test.

UPSC Geologist & Geo-Scientist Application Fee:

Candidates should pay Rs.200/- through depositing money in any branch of SBI by cash or Net Banking of SBI, State Bank of Bikaner & Jaipur/ State Bank of Hyderabad/ Mysore/ Patiala/ Travancore or by using Visa/ Master Credit/ Debit Card. SC/ ST/ PH/ Female candidates are exempted from payment of fee.

How to Apply for UPSC Geologist & Geo-Scientist:

Eligible candidates may apply online through website http://www.upsconline.nic.in/ from 01-03-2014 to 31-03-2014 by 11:59 PM.

Instructions for Applying Online UPSC Geologist & Geo-Scientist:

  • Log on through website http://www.upsconline.nic.in/
  • Candidates are required to complete 2 stages Part-I & Part-II for online application.
  • Pay the Online or offline payment & keep the slip for the future reference.
  • Read all the Instruction carefully & fill all the relevant details carefully.
  • Candidates should have a scanned signature & photograph in .jpg format.
  • Please check your mail frequently & ensure that the email address ending with @nic.in is directed to INBOX not to SPAM or any other folder.
  • After filling the application submit & and take the print out of application for the future use.

Important Dates for UPSC Geologist & Geo-Scientist Post :
Date of Advertisement: 01-03-2014
Last Date for Applying Online: 31-03-2014 by 11:59 PM.
Date of Written Test: 25-05-2014

UPSC Geologist Exam 2014 Information
Selection Process for Geologist
UPSC Geologist Exam  Exam Pattern
Exam Syllabus

We recommend you to read All Questions and Answers about Indian National Congress (INC) for Preparing this competitive exam